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  1. 29. Mai 2022 · Jane Wymark, who played Joyce Barnaby, the wife of DCI Tom Barnaby (played by John Nettles), opened up about starring in the show for 14 years and how her character developed. Related articles

    • 59 Sek.
    • Jamie Body
  2. 28. März 2024 · Jane Wymark was born on October 31, 1952, in Paddington, London, England, UK. She was born to her father Patrick Wymark and mother Olwen Wymark. Her mother, Olwen was an American writer and playwright and her father was a British actor. His father acted in Shakespeare’s plays. Hence, she is glad that her parents were in the same field.

  3. Jane Wymark (born 31 October 1952) is an English actress and portrays the character of Joyce Barnaby on the popular ITV crime drama Midsomer Murders. The daughter of English actor Patrick Wymark (1926–1970) and the American writer and playwright Olwen Wymark, she is known for playing Morwenna...

  4. Jane Wymark is a British actress, best known for her roles on the BBC drama Poldark (1975), as well as the television series Midsomer Murders (1997). She was born on October 31, 1952 in London, England, and is the daughter of American writer and playwright Olwen Wymark and English actor Patrick Wymark, both of whom she credits with instilling a ...

  5. 18. Jan. 2022 · Midsomer murders (Image: ITV) Midsomer Murders is ITV’s much-loved detective series set in the fictional village of Midsomer with DCI John Barnaby in charge of the investigations. Actress Jane Wymark was a huge part of the show, from when it first aired in 1997 to her exit in 2011, playing the character of Joyce Barnaby, the inspector’s wife.

  6. 25. Juli 2019 · Based on the crime novel series by author Caroline Graham, Midsomer Murders follows the efforts of veteran DCI John Barnaby and his young sergeant to solve c...

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    • ally network
  7. 16. März 2024 · Since "DCI Tom Barnaby's" departure from Midsomer, his loving wife "Joyce", played by Jane Wymark, also bid farewell to the series in 2011. Following her time on 'Midsomer Murders', Jane appeared ...

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